.0025=4x^2/40

Solution for .0025=4x^2/40 equation:

.0025=4x^2/40

We move all terms to the left:

.0025-(4x^2/40)=0

We add all the numbers together, and all the variables

-(4x^2/40)+0.0025=0

We get rid of parentheses

-4x^2/40+0.0025=0

We multiply all the terms by the denominator


-4x^2+(0.0025)*40=0

We add all the numbers together, and all the variables

-4x^2+0.1=0

a = -4; b = 0; c = +0.1;
Δ = b2-4ac
Δ = 02-4·(-4)·0.1
Δ = 1.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.6}}{2*-4}=\frac{0-\sqrt{1.6}}{-8}
=-\frac{\sqrt{}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.6}}{2*-4}=\frac{0+\sqrt{1.6}}{-8}
=\frac{\sqrt{}}{-8}
$